template과 typename

template <typename T>
void dump_var(const std::vector<T>& var)
{
    std::vector<T>::const_iterator iter = var.begin();
    conststd::vector<T>::const_iterator iter_end = var.end();

    for (; iter != iter_end; ++iter) {
        dump_var(*iter);
    }
}

위 코드는 다음과 같은 에러를 낸다.
implicit typename is deprecated, please see the documentation for details

다음과 같이 바꾸어 써야 한다.
    std::vector<T>::const_iterator iter = var.begin();
    conststd::vector<T>::const_iterator iter_end = var.end();

   =>제대로 된 해결책
    typename std::vector<T>::const_iterator iter = var.begin();
    const typename std::vector<T>::const_iterator iter_end = var.end();

   => 잘못된 해결책 (같은 에러가 계속 난다.)
    std::vector<typename T>::const_iterator iter = var.begin();
    const typename std::vector<typename T>::const_iterator iter_end = var.end();

참고문서
http://www.gnu.org/software/gcc/bugs.html
-------------------------------------------
The new parser brings a lot of improvements, especially concerning name-lookup.

The "implicit typename" extension got removed (it was already deprecated since GCC 3.1), so that the following code is now rejected, see [14.6]:
template <typename> struct A
{
    typedef int X;
};

template <typename T> struct B
{
    A<T>::X          x;  // error
    typename A<T>::X y;  // OK
};

B<void> b;